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Tony García has sent this one. The solution is not confirmed. The relationship may be simplified. Circles are congruent. This will be corrected later. Labels: circle, equilateral triangle, Square, Trigonometry ![]() by Roland Sampy
Labels: circle, equilateral triangle, proof Tony García from Dominican Republic submitted this one.
It looks like it requires brute force.
Better than being idle I guess! So enjoy...
OK, OK, I see world's changing.
Inaction's fun up to a certain point. Then it becomes straight annoying. Let's start with this simple one for high-schoolers :)
Pure-geometric solution will be appreciated.
We'll build upon this later. Based on the evidence presented by Bleaug, this is updated as follows:
This is just one step forward to the general case. Should not be very hard unless the claim is wrong :)
We'll return back to Sampy's question later. But, for a change let's see a simple one - or at least it looks simple. We're looking for the shortest proof of the claim below. May be purely-geometric one? Or is the claim wrong? Let us know...
Below is the general case submitted by Roland Sampy.
There seems to be at least 2 expressions for r. We had a solution, but it looked a little clumsy. Moreover, we lost it :) Wooow... This has been quite long time, huh? Life makes people busy (although that is not the exact excuse.) Is everybody alive? What have you been up to? Bleaug? Newzad? Polar Fox ?? ...
The following fox is a simplified version submitted by Roland Sampy.
We should be able to ask a general version later. You mean next year??? Who knows hopefully earlier. Here you are... Oh, by the way the answer was not confirmed yet. So, the claim could be wrong.
A new year,
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